2w^2-5w-86=0

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Solution for 2w^2-5w-86=0 equation: 



2w^2-5w-86=0

a = 2; b = -5; c = -86;
Δ = b2-4ac
Δ = -52-4·2·(-86)
Δ = 713
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{713}}{2*2}=\frac{5-\sqrt{713}}{4}
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{713}}{2*2}=\frac{5+\sqrt{713}}{4}
$

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